document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882063>Question 882063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with algebra part 2. I am working on using -1 as a factor to simplify and rational expressions. heres an example:\r<BR>\n" );
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document.write( "-x^2+9 over (or divided by) x+3 and\r<BR>\n" );
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document.write( "8y-5 over 10-16y\r<BR>\n" );
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document.write( "any help is greatly appreciated! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532676 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532676\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x^2+9 over (or divided by) x+3 <BR>\n" );
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document.write( "= -(x+3)(x-3)/(x+2) = -(x+3)\r<BR>\n" );
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document.write( "and <BR>\n" );
document.write( "8y-5 over 10-16y <BR>\n" );
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document.write( "(8y-5)/(-2(8y-5))<BR>\n" );
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document.write( "= 1/(-2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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