document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881966>Question 881966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of the larger circle is 36  Pi in2 Find the circumference of one of the smaller circles. There are two smaller circles inside the larger circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532645 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532645\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the larger circle is 36 Pi in2 Find the circumference of one of the smaller circles. There are two smaller circles inside the larger circle.<BR>\n" );
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document.write( "assume diameter of smaller circles=1/2 that of the larger circle<BR>\n" );
document.write( "&#960;r^2=area <BR>\n" );
document.write( "&#960;r^2=36&#960;<BR>\n" );
document.write( "r^2=36<BR>\n" );
document.write( "r=6 (radius of larger circle)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "r/2=3=radius of smaller circle<BR>\n" );
document.write( "circumference of smaller circle=2&#960;*radius=2&#960;*3=6&#960;=18.85in<BR>\n" );
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