document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74190>Question 74190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve equation for x=log11 1331 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53262 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think what you are expressing is x equals the log to the base 11 of 1331.<BR>\n" );
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document.write( "This can be rewritten in exponential form as:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11%5Ex+=+1331 ALIGN=MIDDLE  ALT=\"11%5Ex+=+1331\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now you can take the log to the base 10 of both sides to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log11%5Ex+=+log+1331 ALIGN=MIDDLE  ALT=\"log11%5Ex+=+log+1331\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "By the rules of logs the exponent x comes out as the multiplier of log 11 to give<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2Alog11+=+log+1331 ALIGN=MIDDLE  ALT=\"x%2Alog11+=+log+1331\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now you can use your calculator in log to the base 10 mode to get that log 11 = 1.041392685.<BR>\n" );
document.write( "Similarly you can use your calculator in log to the base 10 mode to find that log 1331 =<BR>\n" );
document.write( "3.124178055.<BR>\n" );
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document.write( "Substitute these two values into our equation to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A%281.041392685%29+=+3.124178055 ALIGN=MIDDLE  ALT=\"x%2A%281.041392685%29+=+3.124178055\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now solve for x by dividing both sides by 1.041392685 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%283.124178055%29%2F%281.041392685%29+=+3 ALIGN=MIDDLE  ALT=\"x+=+%283.124178055%29%2F%281.041392685%29+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So the answer to this problem is x = 3.<BR>\n" );
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document.write( "Because the values are relatively small, when you got to the exponential form of:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11%5Ex+=+1331 ALIGN=MIDDLE  ALT=\"11%5Ex+=+1331\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You could have just plugged values in for x until you got to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11%5E3+=+1331 ALIGN=MIDDLE  ALT=\"11%5E3+=+1331\"   DISABLED_style= \"max-width:90%; height:auto;\" > but that<BR>\n" );
document.write( "is just a \"test taking\" trick.  The rigorous way to do it is using the procedures above.<BR>\n" );
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document.write( "Hope this helps you to see your way through this problem.  It has some good practice<BR>\n" );
document.write( "with working with logs.<BR>\n" );
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