document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881940>Question 881940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the properties of logarithms to show that log10(2.76 x10^3) can be written as 3+log10 2.76.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532614 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> show that log10(2.76 x10^3) can be written as 3+log10 2.76<BR>\n" );
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document.write( "Multiply --> add logs<BR>\n" );
document.write( "log(2.76 x10^3) = log(2.76) + log(10^3)<BR>\n" );
document.write( "= log(2.76) + 3<BR>\n" );
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document.write( "Base 10 is assumed, if no other base is specified.<BR>\n" );
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