document.write( "Question 881789: The decay of 457mg of an isotope is given by A(t)=457e^-0.019t, where t is time in years. Find the amount left after 78 years. \n" ); document.write( "

Algebra.Com's Answer #532505 by josmiceli(19441) $\"\"$ $\"About$

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$\"+A%28t%29+=+457%2Ae%5E%28-.019t%29+\"$
\n" ); document.write( "Find $\"+A%2878%29+\"$
\n" ); document.write( " $\"+A%2878%29+=+457%2Ae%5E%28-.019%2A78%29+\"$
\n" ); document.write( " $\"+A%2878%29+=+457%2Ae%5E%28-1.482%29+\"$
\n" ); document.write( " $\"+A%2878%29+=+457%2A.22718+\"$
\n" ); document.write( " $\"+A%2878%29+=+103.82+\"$
\n" ); document.write( "103.82 mg are left after 78 years
\n" ); document.write( " \n" ); document.write( "

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