document.write( "Question 881694: if a man walks at 4/5th of his usual rate he reaches office 5 minutes later than usual how many minutes does he usually take to reach his office \n" ); document.write( "
Algebra.Com's Answer #532490 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! if a man walks at 4/5th of his usual rate he reaches office 5 minutes later than usual \n" ); document.write( " how many minutes does he usually take to reach his office \n" ); document.write( ": \n" ); document.write( "let t = his normal time to work (in minutes) \n" ); document.write( "then \n" ); document.write( "(t+5) = his time when he is late \n" ); document.write( ": \n" ); document.write( "Change 4/5 to .8 \n" ); document.write( "let s = his normal rate \n" ); document.write( "then \n" ); document.write( ".8s = his slower rate \n" ); document.write( ": \n" ); document.write( "We don't really need to know his rate but will use it and get rid of it \n" ); document.write( "the distance for each trip is the same \n" ); document.write( "write a distance equation dist = speed * time \n" ); document.write( "st = .8s(t + 5) \n" ); document.write( "divide both sides by s \n" ); document.write( "t = .8(t + 5) \n" ); document.write( "t = .8t + 4 \n" ); document.write( "t - .8t = 4 \n" ); document.write( ".2t = 4 \n" ); document.write( "t = 4/.2 \n" ); document.write( "t = 20 min is his normal time \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |