document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881781>Question 881781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide. If its area is 50 sq. yd., find the length.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532484 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L * W = Area<BR>\n" );
document.write( "L = 2W<BR>\n" );
document.write( "Substitute the value of L from the second equation into the first.<BR>\n" );
document.write( "2W * W = 50<BR>\n" );
document.write( "2W^2 = 50<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "w^2 = 25<BR>\n" );
document.write( "Take the square root of each side<BR>\n" );
document.write( "w = 5<BR>\n" );
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document.write( "If the width is 5, then the length is twice that, or 10.  10*5=50<BR>\n" );
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