document.write( "Question 881678: In a Triangle abc what is the distance between the midpoint of bc and the foot of the perpendicular from a to bc, if the length of the sidesof bc,ca and ab are 5cm,7cm,6cm respectively \n" ); document.write( "

Algebra.Com's Answer #532473 by Edwin McCravy(20055) $\"\"$ $\"About$

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document.write( "Let M be the midpoint of BC\r\n" );
document.write( "Let F be the foot of the perpendicular from A to BC\r\n" );
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document.write( "We find cos(B) by using the law of cosines on triangle ABC\r\n" );
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document.write( "From right triangle ABF,\r\n" );
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document.write( "Since BC=5 and M is the midpoint of BC, and BC = 5,\r\n" );
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document.write( "BM = half of 5 or \r\n" );
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document.write( "FM = BM - BF =  =  =  = 1.3\r\n" );
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document.write( "Edwin

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