document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881613>Question 881613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear Sir/Madam;<BR>\n" );
document.write( "   Kindly help me with this question:  The sum of the first 50 terms of an arithmetic progression is 200 and the sum of the next 50 terms is 2700.  Find the first term.  Thanks a lot! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532466 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S = ½(2a + (n-1)d)n<BR>\n" );
document.write( "2700= ½(2a + (49)d)50<BR>\n" );
document.write( "2700= 25(2a + 49d)<BR>\n" );
document.write( "2700= ½(2a + (49)d)50<BR>\n" );
document.write( "200 = ½(2a + 99d)100\r<BR>\n" );
document.write( "\n" );
document.write( "2700= 25(2a + 49d)<BR>\n" );
document.write( "108=2a + 49d<BR>\n" );
document.write( "200 = 50(2a + 99d)<BR>\n" );
document.write( "108=2a + 49d<BR>\n" );
document.write( "4= 2a + 99d<BR>\n" );
document.write( "104=-50d<BR>\n" );
document.write( "52=-25d<BR>\n" );
document.write( "-52/25=d<BR>\n" );
document.write( "A1 = 2624/25\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );