document.write( "Question 881727: If a woman invested $10,000 at 8% annual interest, how much more must she invest at 9% so that her annual income will exceed $1,250? \n" ); document.write( "
Algebra.Com's Answer #532412 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
If a woman invested $10,000 at 8% annual interest, how much more must she invest at 9% so that her annual income will exceed $1,250?
\n" ); document.write( "***
\n" ); document.write( "let x=amount invested at 9% so annual income will = $1,250\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "9%x+8%(10000)=1250
\n" ); document.write( ".09x+800=1250
\n" ); document.write( ".09x=450
\n" ); document.write( "x=5000
\n" ); document.write( "how much more must she invest at 9% so that her annual income will exceed $1,250? >$5000
\n" ); document.write( "
\n" );