document.write( "Question 881727: If a woman invested $10,000 at 8% annual interest, how much more must she invest at 9% so that her annual income will exceed $1,250? \n" ); document.write( "
Algebra.Com's Answer #532412 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! If a woman invested $10,000 at 8% annual interest, how much more must she invest at 9% so that her annual income will exceed $1,250? \n" ); document.write( "*** \n" ); document.write( "let x=amount invested at 9% so annual income will = $1,250\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "9%x+8%(10000)=1250 \n" ); document.write( ".09x+800=1250 \n" ); document.write( ".09x=450 \n" ); document.write( "x=5000 \n" ); document.write( "how much more must she invest at 9% so that her annual income will exceed $1,250? >$5000 \n" ); document.write( " |