document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881620>Question 881620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of a line perpendicular to a line that has a slope of -2 and goes through (0,-6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532343 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perpendicular lines have slopes which are negative reciprocals.<BR>\n" );
document.write( "If the slope of the given line is -2, <BR>\n" );
document.write( "then the slope of the new line would be 1/2 {the negative reciprocal of -2}\r<BR>\n" );
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document.write( "slope = 1/2 , (0,-6) {slope and point of new line}\r<BR>\n" );
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document.write( "y - y1 = m(x - x1) {point-slope form}<BR>\n" );
document.write( "y - (-6) = (1/2)(x - 0) {substituted into point-slope form}<BR>\n" );
document.write( "y + 6 = (1/2)x {simplified}<BR>\n" );
document.write( "y = (1/2)x - 6 {subtracted 6 from each side to get into slope-intercept form}<BR>\n" );
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