document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74234>Question 74234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help setting up this problem so I can solve it. Can anyone please help? \r<BR>\n" );
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document.write( "A motor boat can run 25 mph in still water. The boat starts at 7:00 am going upstream in a river whose current runs at 5 mph. How far up the river can the boat go and still be back at 12:00 noon? \r<BR>\n" );
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document.write( "Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53234 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME. THE TWO DISTANCES ARE THE SAME THUS WE HAVE:<BR>\n" );
document.write( "20X=30(5-X)<BR>\n" );
document.write( "20X=150-30X<BR>\n" );
document.write( "20X=30X=150<BR>\n" );
document.write( "50X=150<BR>\n" );
document.write( "X=150/50<BR>\n" );
document.write( "X=3 HOURS GOING UP STEAM. THUS 2 HOURS(5-3=2) RETURN DOWN STREAM.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "20*3=30(5-3)<BR>\n" );
document.write( "60=30*2<BR>\n" );
document.write( "60=60 </SPAN>\n" );
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