document.write( "Question 881419: Solve the following equation for 0 ≤ x ≤ 2π(give answers in exactly in terms of π):
\n" ); document.write( "2cos(π/5 - 5𝑥/2)= √3
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #532289 by lwsshak3(11628) $\"\"$ $\"About$

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Solve the following equation for 0 ≤ x ≤ 2π(give answers in exactly in terms of π):
\n" ); document.write( "2cos(π/5 - 5𝑥/2)= √3
\n" ); document.write( "cos(π/5 - 5𝑥/2)= √3/2
\n" ); document.write( " $\"pi%2F5-5x%2F2=pi%2F6\"$ (in quadrant I in which cos>0)
\n" ); document.write( "lcd:30
\n" ); document.write( "6π-75x=5π
\n" ); document.write( "75x=π
\n" ); document.write( "x=π/75
\n" ); document.write( "..
\n" ); document.write( " $\"pi%2F5-5x%2F2=11pi%2F6\"$ (in quadrant IV in which cos>0)
\n" ); document.write( "lcd:30
\n" ); document.write( "6π-75x=55π
\n" ); document.write( "75x=-49π
\n" ); document.write( "x=-49π/75 \n" ); document.write( "

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