document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74162>Question 74162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i am having trouble with functions.  could you please help solve this question?\r<BR>\n" );
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document.write( "If f(x)=x^3-2x+1 then f(2/3)=\r<BR>\n" );
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document.write( "i figured -1/27 was the answer but i am not sure. thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53228 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F(2/3)=(2/3)^3-2(2/3)+1<BR>\n" );
document.write( "F(2/3)=(8/27)-4/3+1<BR>\n" );
document.write( "F(2/3)=(8+9*-4+27)/27<BR>\n" );
document.write( "F(2/3)=(8-36+27)/27<BR>\n" );
document.write( "F(2/3)=-1/27<BR>\n" );
document.write( "RIGHT ON!!!!!!!!!!!!!!!  : ) </SPAN>\n" );
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