document.write( "Question 876770: 3 ladies &3 gents can be seated at a round table so that any two & only two of the ladies sit together.the number of ways is \n" ); document.write( "
Algebra.Com's Answer #532266 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "There are only these two GENERAL ways to seat them. [Rotations of\r\n" ); document.write( "these two are not counted as separate GENERAL seating arrangements.] \r\n" ); document.write( "\r\n" ); document.write( " L L\r\n" ); document.write( " L G L G \r\n" ); document.write( " \r\n" ); document.write( " G L G G \r\n" ); document.write( " G L\r\n" ); document.write( "\r\n" ); document.write( "Choose the GENERAL way to seat the 6 in 2 ways.\r\n" ); document.write( "Arrange the gents in the three G seats in 3! SPECIFIC ways.\r\n" ); document.write( "Arrange the ladies in the three L seats in 3! SPECIFIC ways.\r\n" ); document.write( "\r\n" ); document.write( "Answer: 2*3!*3! = 2*6*6 = 72 ways. \r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |