document.write( "Question 881431: 10 year ago the age of A was half as old as B.if the ratio of there present age is 3:4,then the sum of there present age is?\r
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Algebra.Com's Answer #532256 by ankor@dixie-net.com(22740)\"\" \"About 
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10 year ago the age of A was half as old as B.
\n" ); document.write( "\"%28%28A-10%29%29%2F%28%28B-10%29%29\" = \"1%2F2\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "B - 10 = 2(A-10)
\n" ); document.write( "B - 10 = 2A - 20
\n" ); document.write( "B = 2A - 20 + 10
\n" ); document.write( "B = 2A - 10
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\n" ); document.write( "if the ratio of there present age is 3:4,
\n" ); document.write( "\"A%2FB\" = \"3%2F4\"
\n" ); document.write( "4A = 3B
\n" ); document.write( "Replace B with (2A-10)
\n" ); document.write( "4A = 3(2A-10)
\n" ); document.write( "4A = 6A - 30
\n" ); document.write( "30 = 6A - 4A
\n" ); document.write( "30 = 2A
\n" ); document.write( "A = 30/2
\n" ); document.write( "A = 15 is A's age
\n" ); document.write( "then
\n" ); document.write( "B = 2(15) - 10
\n" ); document.write( "B = 20 yrs is B's age
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\n" ); document.write( "Then the sum of there present age is? 35
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