document.write( "Question 881431: 10 year ago the age of A was half as old as B.if the ratio of there present age is 3:4,then the sum of there present age is?\r
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Algebra.Com's Answer #532256 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 10 year ago the age of A was half as old as B. \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "B - 10 = 2(A-10) \n" ); document.write( "B - 10 = 2A - 20 \n" ); document.write( "B = 2A - 20 + 10 \n" ); document.write( "B = 2A - 10 \n" ); document.write( ": \n" ); document.write( "if the ratio of there present age is 3:4, \n" ); document.write( " \n" ); document.write( "4A = 3B \n" ); document.write( "Replace B with (2A-10) \n" ); document.write( "4A = 3(2A-10) \n" ); document.write( "4A = 6A - 30 \n" ); document.write( "30 = 6A - 4A \n" ); document.write( "30 = 2A \n" ); document.write( "A = 30/2 \n" ); document.write( "A = 15 is A's age \n" ); document.write( "then \n" ); document.write( "B = 2(15) - 10 \n" ); document.write( "B = 20 yrs is B's age \n" ); document.write( ": \n" ); document.write( "Then the sum of there present age is? 35 \n" ); document.write( ": \n" ); document.write( " |