document.write( "Question 881259: Find the solution to the given trig equation for 0 is less than or equal to 0 is less than or equal to 2.
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document.write( "sin^2 x - sinx = cos^2x \n" );
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Algebra.Com's Answer #532250 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the solution to the given trig equation for 0 is less than or equal to 0 is less than or equal to 2pi \n" ); document.write( " sin^2 x - sinx = cos^2x \n" ); document.write( "----------------- \n" ); document.write( "sin^2(x) - sin(x) = 1 - sin^2(x) \n" ); document.write( "------ \n" ); document.write( "2sin^2(x) - sin(x) - 1 = 0 \n" ); document.write( "------ \n" ); document.write( "(2sin(x)+1)(sin(x)-1) = 0 \n" ); document.write( "------- \n" ); document.write( "sin(x) = -1/2 or sin(x) = 1 \n" ); document.write( "---------------------------------- \n" ); document.write( "If sin(x) = -1/2, x = (7/6)pi or x = (11/6)pi \n" ); document.write( "------ \n" ); document.write( "If sin(x) = 1, x = pi/2 \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------- \n" ); document.write( " |