document.write( "Question 881466: what is the area of a rectangle whose width is 10 in. and whose diagonal measures 26 in \n" ); document.write( "
Algebra.Com's Answer #532247 by Chester2020(1)\"\" \"About 
You can put this solution on YOUR website!
(REFER's ANSWER IS WRONG!)(24x10) NOT (24x26) (26 is the hypotenuse!!!!)In the pythagorean theorem As + Bs = Cs (s) meaning (square)the diagonal line is hypotenuse and since your using a rectangle all the corners are right angles so this is going to be a 30 45 90 degree right triangle or just call it Leg Leg Hypotenuse. so first you have to find the other side of the rectangle which should also be the last side of your rectangle if i pictured it right.\r
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\n" ); document.write( "leg1 or As = 10s
\n" ); document.write( "Leg2= Bs
\n" ); document.write( "hypotenuse or Cs = 26s\r
\n" ); document.write( "\n" ); document.write( "10s+Bs=26s (square them) = 100+Bs=676\r
\n" ); document.write( "\n" ); document.write( "then simplify as you would do in your normal algebra\r
\n" ); document.write( "\n" ); document.write( " 100+Bs=676
\n" ); document.write( "-100 -100
\n" ); document.write( "-------------
\n" ); document.write( "Bs=576s
\n" ); document.write( "square root of 576=(24)<--Leg2\r
\n" ); document.write( "\n" ); document.write( "now you can get the area (10in X 24in = 240in. square)\r
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