document.write( "Question 881459: \"The width of a rectangular room is 10 feet less than its length. The area of the room is 375 square feet. Find the width and length of the room.\"\r
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document.write( "I started out with 2L+2(L-10)=357
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document.write( "2L+2L-20=357\r
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document.write( "4L=377\r
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document.write( "4L/4=377/4\r
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document.write( "L=94.25 square feet.\r
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document.write( "I don't feel like this is the right answer. I appreciate the help! Thanks!\r
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Algebra.Com's Answer #532227 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Did you check it? \n" ); document.write( "if 94.25 is the length what is the width? \n" ); document.write( "84.25-10 is the width \n" ); document.write( "94.25*84.25=7940.5625 \n" ); document.write( "you used the formula for circumference not area!\r \n" ); document.write( "\n" ); document.write( "you want L*w=375 \n" ); document.write( "L*(L-10)=375 \n" ); document.write( "L^2-10L-375=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "the solver doesn't like L \n" ); document.write( "discard negative answers \n" ); document.write( "x-25=0 \n" ); document.write( "L=25 \n" ); document.write( "W=15 \n" ); document.write( " \n" ); document.write( " |