document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881397>Question 881397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Jones has three children. The youngest two children are twins. Find the ages of each of the three children if the difference between the oldest and youngest is three years and the sum of the ages of all children is 30. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532194 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mrs. Jones has three children. The youngest two children are twins. Find the ages of each of the three children if the difference between the oldest and youngest is three years and the sum of the ages of all children is 30.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=age of oldest child<BR>\n" );
document.write( "x-3=age of twins<BR>\n" );
document.write( "x+2(x-3)=30<BR>\n" );
document.write( "x+2x-6=30<BR>\n" );
document.write( "3x=24<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "x-3=5<BR>\n" );
document.write( "age of oldest child=8<BR>\n" );
document.write( "age of twins=5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );