document.write( "Question 881377: Find the vertex, focus and directrix and the correct graph of the equation 12(x+5)=y-8)^2 \n" ); document.write( "
Algebra.Com's Answer #532189 by lwsshak3(11628)\"\" \"About 
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Find the vertex, focus and directrix and the correct graph of the equation 12(x+5)=y-8)^2
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\n" ); document.write( "12(x+5)=y-8)^2
\n" ); document.write( "(y-8)^2=12(x+5)
\n" ); document.write( "This is an equation of a parabola that opens rightward
\n" ); document.write( "Its basic equation: (y-k)^2=4p(x-h), (h,k)=coordinates of the vertex
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex: (-5,8)
\n" ); document.write( "axis of symmetry: y=8
\n" ); document.write( "4p=12
\n" ); document.write( "p=4
\n" ); document.write( "focus: (-1,8) (p-distance to the right of vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=-9 (p-distance to the left of vertex on the axis of symmetry)
\n" ); document.write( "see graph below:
\n" ); document.write( "y=±(12x+60)^.5+8\r
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