document.write( "Question 881356: the length of a rectangle is 7 feet less than twice the width. find the deminsions if the area is 99 square feet? \n" ); document.write( "
Algebra.Com's Answer #532173 by Fombitz(32388)\"\" \"About 
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\"L=W-7\"
\n" ); document.write( "For a rectangle,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "\"%28W-7%29W=99\"
\n" ); document.write( "\"W%5E2-7W=99\"
\n" ); document.write( "\"W%5E2-7W-99=0\"
\n" ); document.write( "\"%28W%5E2-7W%2B49%2F4%29-49%2F25-99=0\"
\n" ); document.write( "\"%28W-7%2F2%29%5E2-49%2F4-396%2F4=0\"
\n" ); document.write( "\"%28W-7%2F2%29%5E2=445%2F4\"
\n" ); document.write( "\"W-7%2F2=0+%2B-+sqrt%28445%29%2F2\"
\n" ); document.write( "\"W=7%2F2+%2B-+sqrt%28445%29%2F2\"
\n" ); document.write( "Only a positive width makes sense in this situation,
\n" ); document.write( "\"W=7%2F2%2B+sqrt%28445%29%2F2\"
\n" ); document.write( "Then,
\n" ); document.write( "\"L=7%2F2%2Bsqrt%28445%29%2F2-7\"
\n" ); document.write( "\"L=-7%2F2%2Bsqrt%28445%29%2F2\"\r
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