document.write( "Question 881287: find the area of the minor segment of a circle whose radius is 8 and has a central angle of 60. Use π =3.14 and round your answer to the nearest tenth.\r
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document.write( "I tried to figure it out and i got 5.6, i don't know if its correct, im kind of confused. Please help me! \n" );
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Algebra.Com's Answer #532096 by dkppathak(439) You can put this solution on YOUR website! find the area of the minor segment of a circle whose radius is 8 and has a central angle of 60. Use π =3.14 and round your answer to the nearest tenth. \n" ); document.write( "area of minor segment = area of sector - area of triangle formed at center(1) \n" ); document.write( "area of sector with center angle 60 degree =center angle x (pie r^2)/360 \n" ); document.write( " =60 x3.14 x8 x8/360 \n" ); document.write( " =3.14 x64/6 =33.4933 \n" ); document.write( "area of triage formed at center = r^2 sin(center angle) /2 \n" ); document.write( " =8^2 sin 60/2 \n" ); document.write( " =64 x sqrt3/4 =16 sqrt3=16 x1.7320=27.7128 \n" ); document.write( " area of minor segment = area of sector - area of triangle formed at center \n" ); document.write( " =33.4933-27.7128 =5.7805 \n" ); document.write( "Answer \n" ); document.write( "Area of minor segment = 5.7805\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 \n" ); document.write( " \n" ); document.write( " |