document.write( "Question 881274: a garden is shaped like a rectangle whose perimeter is 66 ft. The length is 9 ft more than the width. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #532077 by JulietG(1812)\"\" \"About 
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A perimeter is a fence around. 2 lengths and 2 width = perimeter (2W + 2L = P)
\n" ); document.write( "L = W + 9
\n" ); document.write( "Substitute the value of L from the second equation into the first.
\n" ); document.write( "2W + 2(W+9) = 66
\n" ); document.write( "Distribute
\n" ); document.write( "2W + 2W + 18 = 66
\n" ); document.write( "Add
\n" ); document.write( "4W + 18 = 66
\n" ); document.write( "Subtract 18 from each side
\n" ); document.write( "4W = 48
\n" ); document.write( "Divide each side by 4
\n" ); document.write( "W = 12
\n" ); document.write( ".
\n" ); document.write( "If the width is 12, then the length is 12+9, or 21.
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