document.write( "Question 9783: One number is 2 Times another. If you subtract 10 from each number, the sum is 40, what are the numbers? \n" ); document.write( "

Algebra.Com's Answer #5320 by Earlsdon(6294) $\"\"$ $\"About$

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Let x be the 1st number and y be the 2nd number.\r
\n" ); document.write( "\n" ); document.write( "Then:\r
\n" ); document.write( "\n" ); document.write( " $\"x+=+2y\"$ and
\n" ); document.write( " $\"%28x-10%29+%2B+%28y-10%29+=+40\"$ Substiute x = 2y from the 1st equation.\r
\n" ); document.write( "\n" ); document.write( " $\"%282y-10%29+%2B+%28y-10%29+=+40\"$ Simplify and solve for y.\r
\n" ); document.write( "\n" ); document.write( " $\"3y+-20+=+40\"$ Add 40 to both sides.\r
\n" ); document.write( "\n" ); document.write( " $\"3y+=+60\"$ Divide both sides by 3.\r
\n" ); document.write( "\n" ); document.write( " $\"y+=+20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+=+2y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+=+2%2820%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+=+40\"$ \r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( " $\"x+=+2y\"$
\n" ); document.write( " $\"40+=+2%2820%29\"$ \r
\n" ); document.write( "\n" ); document.write( "and:\r
\n" ); document.write( "\n" ); document.write( " $\"%28x-10%29+%2B+%28y-10%29=+%2840-10%29+%2B+%2820-10%29\"$ = $\"30+%2B+10+=+40\"$
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