document.write( "Question 881138: f(x) = x^3 - 12x - 1\r
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\n" ); document.write( "\n" ); document.write( "f(x)=(x/x^2+3)^3
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Algebra.Com's Answer #531996 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
f(x) = x^3 - 12x - 1
\n" ); document.write( "f'(x) = 3x^2 - 12 = 0, x^2 = 4, x = ± 2
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