document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881103>Question 881103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a manufacturer of tow chains finds that the average breaking point is at 3,500 pounds and the standard deviation is 250 pounds. if you pull a weight of at least 3000 pounds with this tow chain, what percentage of time would you expect the chain to break </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531974 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean = 3,500 pounds and the standard deviation is 250 pounds.<BR>\n" );
document.write( "*Note: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=z+=+blue%28x+-+mu%29%2Fblue%28sigma%29 ALIGN=MIDDLE  ALT=\"z+=+blue%28x+-+mu%29%2Fblue%28sigma%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "P(x &#8805; 3000) = 1 - P(z < 2) = 1 - 87.72% = 2.28% of the time would expect the chain to break </SPAN>\n" );
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