document.write( "Question 881026: You have 50 yards (50-2x) of fencing to enclose a rectangular region. Find the dimensions of the rectangle that maximize the enclosed area. What is the maximum area? This involves quadratic functions if that makes it easier to understand. \n" ); document.write( "
Algebra.Com's Answer #531960 by Fombitz(32388)\"\" \"About 
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The perimeter of the rectangle is,
\n" ); document.write( "\"P=2%28L%2BW%29=50\"
\n" ); document.write( "\"L%2BW=25\"
\n" ); document.write( "The area of the rectangle is,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "Substitute from above,
\n" ); document.write( "\"L=25-W\"
\n" ); document.write( "\"A=%2825-W%29W\"
\n" ); document.write( "\"A=25W-W%5E2\"
\n" ); document.write( "Differentiate with respect to W and set the derivative equal to zero.
\n" ); document.write( "\"dA%2FdW=25-2W=0\"
\n" ); document.write( "\"2W=25\"
\n" ); document.write( "\"W=25%2F2\"
\n" ); document.write( "Then,
\n" ); document.write( "\"L=25%2F2\"
\n" ); document.write( "The maximum area for a given perimeter is a square.
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