document.write( "Question 881039: a father is twice as old as his son. 12 years ago the father was 4 times as old as the son was then.
\n" ); document.write( "Determine their present age.
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Algebra.Com's Answer #531941 by algebrahouse.com(1659)\"\" \"About 
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x = son's age
\n" ); document.write( "2x = father's age {he is twice as old as his son}\r
\n" ); document.write( "\n" ); document.write( "x - 12 = son's age 12 years ago
\n" ); document.write( "2x - 12 = father's age 12 years ago\r
\n" ); document.write( "\n" ); document.write( "2x - 12 = 4(x - 12) {twelve years ago the father was 4 times his son}
\n" ); document.write( "2x - 12 = 4x - 48 {used distributive property}
\n" ); document.write( "-12 = 2x - 48 {subtracted 2x from each side}
\n" ); document.write( "36 = 2x {added 48 to each side}
\n" ); document.write( "x = 18 {divided each side by 2}
\n" ); document.write( "2x = 36 {substituted 18, in for x, into 2x}\r
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\n" ); document.write( "\n" ); document.write( "son is 18
\n" ); document.write( "father is 36
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