document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881058>Question 881058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the fifteenth term in an arithmetic sequence is 43 and the sum of the first 15 terms of the series is 120. determine the first three terms of the sequence.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531928 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the fifteenth term in an arithmetic sequence is 43 and the sum of the first 15 terms of the series is 120. determine the first three terms of the sequence.<BR>\n" );
document.write( "T15= a+14d=43  (1)<BR>\n" );
document.write( "S15= 15(2a+14d)/2 =120   (2)<BR>\n" );
document.write( "15(a+a+14d)/2 =120  by substituting a+14d=43 in (2)<BR>\n" );
document.write( "15(a+43)/2=120<BR>\n" );
document.write( "a+43=120x2/15<BR>\n" );
document.write( "a+43=16<BR>\n" );
document.write( "a=16-43 =-27<BR>\n" );
document.write( "a+14d=43<BR>\n" );
document.write( "-27 +14d = 43<BR>\n" );
document.write( "14d=43+27<BR>\n" );
document.write( "14d = 70<BR>\n" );
document.write( "d=70/14 =5<BR>\n" );
document.write( "Answer  first terms= -27<BR>\n" );
document.write( "        Second term = -27+5 =-22<BR>\n" );
document.write( "        third term  = -27+2x5 =-27 +10= -17\r<BR>\n" );
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document.write( " </SPAN>\n" );
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