document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=881037>Question 881037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in an examination a student score 4 mark for every correct ans and lose 1 mark for every wrong ans if he attempts in all 60 question and secures 130 mark what no of question does he attempts correctly.\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531887 by </B><A HREF=/tutors/aboutme.mpl?userid=sl.ahmed><B>sl.ahmed(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sl.ahmed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sl.ahmed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let, no of correct attemd is x\n" );
document.write( "then, \n" );
document.write( "4x - 1*(60-x) = 130\n" );
document.write( "=> 4x - 60   x = 130\n" );
document.write( "=> 5x = 190\n" );
document.write( "=> x = 38\n" );
document.write( "there for answer 38 </SPAN>\n" );
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