document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880933>Question 880933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the five-step strategy for solving word problems to find the number or numbers described in the following exercise.\r<BR>\n" );
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document.write( "One number exceeds another by -5. The sum of the numbers is 11. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531881 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = B - 5 (this is no good as a word problem because it cannot 'exceed' by a negative number).<BR>\n" );
document.write( "A + B = 11<BR>\n" );
document.write( "Substitute the known value of A from the first equation into the second.<BR>\n" );
document.write( "(B-5) + B = 11<BR>\n" );
document.write( "Add<BR>\n" );
document.write( "2B - 5 = 11<BR>\n" );
document.write( "Add 5 to each side<BR>\n" );
document.write( "2B = 16<BR>\n" );
document.write( "Divide<BR>\n" );
document.write( "B = 8<BR>\n" );
document.write( "Therefore, A = 8-5, or 3. </SPAN>\n" );
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