document.write( "Question 881017: 2kg of tea and 3kg of sugar together costs Rs.39. the price of tea has risen by 25% and that of sugar by 20% hence the same quantities of tea and sugar now cost Rs.48.30. find the original price of tea per kg? \n" ); document.write( "
Algebra.Com's Answer #531867 by dkppathak(439)\"\" \"About 
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2kg of tea and 3kg of sugar together costs Rs.39. the price of tea has risen by 25% and that of sugar by 20% hence the same quantities of tea and sugar now cost Rs.48.30. find the original price of tea per kg?
\n" ); document.write( "let cost of 1 kg tea is Rs x cost of sugar is Rs y
\n" ); document.write( "as per given condition 1
\n" ); document.write( "2X +3Y =39 (1)
\n" ); document.write( "as per condition 2 price increase 25% and 20% respectively
\n" ); document.write( "1.25(2x) + 1.2(3y) = 48.30
\n" ); document.write( "2.50x + 3.6 Y =48.30 multiply by 10 for simplification of equation
\n" ); document.write( "25x + 36Y = 483 (2) multiply (1) by 25 and (2) by 2 for solution
\n" ); document.write( "50x +75Y = 975 (3)
\n" ); document.write( "50x + 72 Y = 966 (4) subtracting
\n" ); document.write( "3y=9
\n" ); document.write( "Y= 3
\n" ); document.write( "substituting value of Y in (1)
\n" ); document.write( "2x +3y =39
\n" ); document.write( "2x +9=39
\n" ); document.write( "2x=30
\n" ); document.write( "X=30/2=15
\n" ); document.write( "Answer
\n" ); document.write( "cost of 1 kg tea is Rs 15
\n" ); document.write( "cost of 1 kg sugar is Rs 3 \r
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