document.write( "Question 881000: sin(4x)cos(3x)+cos(4x)sin(3x)=0.51
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Algebra.Com's Answer #531862 by Edwin McCravy(20056) $\"\"$ $\"About$

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document.write( "sin(4x)cos(3x)+cos(4x)sin(3x)=0.51\r\n" );
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document.write( "Use the identity\r\n" );
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document.write( "Substitute , :\r\n" );
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document.write( "or\r\n" );
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document.write( "The right side equals to 0.51.  \r\n" );
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document.write( "Take inverse sines of both sides:\r\n" );
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document.write( "  sin^-1(0.51) + \r\n" );
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document.write( "also\r\n" );
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document.write( "  ( - sin^-1(0.51) + )\r\n" );
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document.write( "  -sin^-1(0.51) + )\r\n" );
document.write( "Therefore, solving for x in each\r\n" );
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document.write( "  sin^-1(0.51) + \r\n" );
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document.write( "also\r\n" );
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document.write( "  sin^-1(0.51) + )\r\n" );
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document.write( "To get the two fundamental solutions let n=0 in each:\r\n" );
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document.write( "  sin^-1(0.51)\r\n" );
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document.write( "and\r\n" );
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document.write( "  sin^-1(0.51) + \r\n" );
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document.write( "Edwin

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