document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880917>Question 880917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a geometric progression of positive terms, the 5th term is 9 times the 3rd term and the sum of the 6th and 7th terms is 972. Find the <BR>\n" );
document.write( "a) common ratio<BR>\n" );
document.write( "b) sum of the first 6 terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531824 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)<BR>\n" );
document.write( "common ratio r=3<BR>\n" );
document.write( "b)<BR>\n" );
document.write( "Tn = T1 * r^(n - 1)<BR>\n" );
document.write( "T7 = T1 * 3^(6)<BR>\n" );
document.write( "T6 = T1 * 3^(5)<BR>\n" );
document.write( "T7 +T6 =972\r<BR>\n" );
document.write( "\n" );
document.write( "T1 * 3^(5)+ t * 3^(6)=972<BR>\n" );
document.write( "T1*(3^5+3^6)=972<BR>\n" );
document.write( "T1*243+729=972<BR>\n" );
document.write( "T1*972=972<BR>\n" );
document.write( "T1=1<BR>\n" );
document.write( "S=T1*(1 - r^n)/(1 - r)<BR>\n" );
document.write( "S=1*(1 - 3^6)/(1 - 3)<BR>\n" );
document.write( "S=(1 - 3^6)/(1 - 3)<BR>\n" );
document.write( "S=(1-729)/-2<BR>\n" );
document.write( "S=-728/-2<BR>\n" );
document.write( "S=364\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );