document.write( "Question 880936: suppose you have entered a 121-mile biathlon that consists of a run and bicycle race. During your run, your average velocity is 6 miles per hours, and during your bicycle race, your average velocity is 23 miles per hour. You finish the race in 6 hours. What is the distance of the run? What is the distance of the bicycle race? \n" ); document.write( "
Algebra.Com's Answer #531815 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
suppose you have entered a 121-mile biathlon that consists of a run and bicycle race. During your run, your average velocity is 6 miles per hours, and during your bicycle race, your average velocity is 23 miles per hour. You finish the race in 6 hours. What is the distance of the run? What is the distance of the bicycle race?
\n" ); document.write( "***
\n" ); document.write( "let x=distance of the running race
\n" ); document.write( "121-x=distance of the bicycle race
\n" ); document.write( "travel time=distance/velocity
\n" ); document.write( "..
\n" ); document.write( "\"x%2F6%2B%28121-x%29%2F23=6\"
\n" ); document.write( "lcd=6*23=138
\n" ); document.write( "23x+6(121-x)=6*138
\n" ); document.write( "23x+726-6x=828
\n" ); document.write( "17x=102
\n" ); document.write( "x=6
\n" ); document.write( "121-x=115
\n" ); document.write( "distance of the running race = 6 miles
\n" ); document.write( "distance of the bicycle race=115 miles
\n" ); document.write( "
\n" );