document.write( "Question 878674: sum of series terms is \r
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document.write( "a.\r
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document.write( "b.9841\r
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document.write( "c.9841/root3\r
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document.write( "d.none of these \n" );
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Algebra.Com's Answer #531755 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! S=(1/sqrt(3))*(1 - sqrt(3)^18)/(1 - sqrt(3)) \n" ); document.write( "a.9841(1+root3)/root3 \n" ); document.write( " |