document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880834>Question 880834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having trouble with infinite series... Actually with all algebra. But,<BR>\n" );
document.write( "Question: Find the sum of these infinite series. If it is not possible, write \"no sum\" and explain why.\r<BR>\n" );
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document.write( "1)    1024 + 512 + 256 +128 + ...\r<BR>\n" );
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document.write( "2)    1/9 + 1/3 + 1 + 3 +...\r<BR>\n" );
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document.write( "3)    16 + 4 + 1 + 1/4 +... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531743 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An infinite geometric series converges if its common ratio r satisfies –1 < r < 1.<BR>\n" );
document.write( "Sum=(a1/1-r)<BR>\n" );
document.write( "1)r=1/2<BR>\n" );
document.write( "Sum=(1024/1-1/2=1024/1/2=2048<BR>\n" );
document.write( "2) no sum r=3  which is greater than 1<BR>\n" );
document.write( "3) r=1/4<BR>\n" );
document.write( "Sum=16/(1-1/4)=16/(3/4)=64/3=21.333\r<BR>\n" );
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