document.write( "Question 880773: Town X and Town Y are 220km apart. Sharon left Town X at 08 00 and drove towards Town Y at a speed of 80 km/h. Half an hour later, Michelle started driving from Town Y to Town X. They met each other at 09 15.
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document.write( "(a) What was Michelle's average speed?\r
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document.write( "(b) After passing Michelle, Sharon increased her speed by 10km/h. At what time did she reach Town Y? \n" );
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Algebra.Com's Answer #531687 by Boyen(12)![]() ![]() ![]() You can put this solution on YOUR website! First calculate the place Sharon is at at 9 15. \n" ); document.write( "80 km/h over 1 hour and 15 minutes = 100km \n" ); document.write( "Now you know that Michelle rode the other 120km in 45 minutes. \n" ); document.write( "120km in 45 minutes = 160 km/h \n" ); document.write( "So a)Michelle's average speed was 160km/h\r \n" ); document.write( "\n" ); document.write( "for b: \n" ); document.write( "Again first calculate the place sharon is at at 9 15. \n" ); document.write( "80 km/h over 1 hour and 15 minutes = 100km. \n" ); document.write( "Now you know that she will drive the other 120 km at 90 km/h \n" ); document.write( "120 km over 90 km/h = 1 hour and 20 minutes. \n" ); document.write( "1 hour and 20 min + 1 hour and 15 min = 2 hours and 35 minutes. \n" ); document.write( "So b) Sharon reached town Y at 10:35. \n" ); document.write( " \n" ); document.write( " |