document.write( "Question 880752: A solution that is 50% alcohol is mixed with a solution that is 40% alcohol in order to make\r
\n" ); document.write( "\n" ); document.write( " 50 liters of a solution that is 46% alcohol. How many liters of the 40% solution and how\r
\n" ); document.write( "\n" ); document.write( " many liters of the 50% solution should be used?\r
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Algebra.Com's Answer #531660 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "alcohol I 40.00% ---------------- x liters
\n" ); document.write( "alcohol ii 50.00% ------ 50 - x liters
\n" ); document.write( "Mixture 46.00% ---------------- 50
\n" ); document.write( "Total 50 liters
\n" ); document.write( "40.00% x + 50.00% ( 50 - x ) = 46.00% * 50
\n" ); document.write( "40 x + 50 ( 50 - x ) = 2300
\n" ); document.write( "40 x + 2500 - 50 x = 2300
\n" ); document.write( "40 x - 50 x = 2300 - -2500
\n" ); document.write( "-10 x = -200
\n" ); document.write( "/ -10
\n" ); document.write( " x = 20 liters 40.00% alcohol I
\n" ); document.write( " 30 liters 50.00% alcohol ii
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