document.write( "Question 74038: SOLVE THE INEQUALITY 21 OVER 15-3x <0, AND EXPRESS THE SOLUTION AS AN INTERVAL. \n" ); document.write( "

Algebra.Com's Answer #53166 by cathieb1225(41) $\"\"$ $\"About$

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21/15-3x<0
\n" ); document.write( "simplify 21/15 by dividing both the numerator and the denominator by 3
\n" ); document.write( "7/5-3x<0
\n" ); document.write( "subtract 7/5 from both sides to have the variable term standing alone on one side
\n" ); document.write( "7/5-7/5-3x<0-7/5
\n" ); document.write( "-3x<-7/5
\n" ); document.write( "divide both sides by negative three and \"flip\" the inequality sign because it is division by a negative number
\n" ); document.write( "-3x/-3>-7/5/-3
\n" ); document.write( "dividing -7/5 by negative three is the same thing as multiplying by -1/3
\n" ); document.write( "x>-7/5 * -1/3
\n" ); document.write( "x>7/15
\n" ); document.write( "(7/15,infinity)
\n" ); document.write( "normally one would put the infinity sign within the parentheses, but I did not have one; it looks like an eight laying down on its side. \n" ); document.write( "

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