document.write( "Question 880747: An executive invests $25,000, some at 5% and some at 4% annual interest. If he receives an annual return of $1,150, how much is invested at each rate?\r
\n" ); document.write( "\n" ); document.write( "at 5% interest
\n" ); document.write( "at 4% interest \n" ); document.write( "
Algebra.Com's Answer #531658 by mananth(16946)\"\" \"About 
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Part I 5.00% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 25000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "5.00% x + 4.00% y= 1150
\n" ); document.write( "Multiply by 100
\n" ); document.write( "5 x + 4 y= 115000.00 --------2
\n" ); document.write( "Multiply (1) by -5
\n" ); document.write( "we get
\n" ); document.write( "-5 x -5 y= -125000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -1 y= -10000
\n" ); document.write( "divide by -1
\n" ); document.write( " y = 10000
\n" ); document.write( "Part I 5.00% $ 15000
\n" ); document.write( "Part II 4.00% $ 10000
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\n" ); document.write( "CHECK
\n" ); document.write( "15000 --------- 5.00% ------- 750.00
\n" ); document.write( "10000 ------------- 4.00% ------- 400.00
\n" ); document.write( "Total -------------------- 1150.00
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\n" ); document.write( "m.ananth@hotmail.ca
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