document.write( "Question 880715: I need help finding the equation for this word problem.
\n" ); document.write( "Meredith drove at an average speed of 55 mi/h from her home in Kansas City to visit her sister in Pittsburg. She stayed in Pittsburg 15 hours, and on the trip back averaged 50 mi/h. She returned home 46 hours after leaving. How many miles is Kansas City from Pittsburg?
\n" ); document.write( "Write an equation using the information as it is given above that can be solved to answer this question. Use t as your variable to represent the amount of time Meredith spent driving from Kansas City to Pittsburg. \n" ); document.write( "
Algebra.Com's Answer #531639 by ankor@dixie-net.com(22740)\"\" \"About 
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Meredith drove at an average speed of 55 mi/h from her home in Kansas City to visit her sister in Pittsburg.
\n" ); document.write( " She stayed in Pittsburg 15 hours, and on the trip back averaged 50 mi/h.
\n" ); document.write( " She returned home 46 hours after leaving.
\n" ); document.write( " How many miles is Kansas City from Pittsburg?
\n" ); document.write( "Write an equation using the information as it is given above that can be solved to answer this question.
\n" ); document.write( " Use t as your variable to represent the amount of time Meredith spent driving from Kansas City to Pittsburg.
\n" ); document.write( ":
\n" ); document.write( "Let t = amt of time to drive from K.C to Pitts
\n" ); document.write( ":
\n" ); document.write( "subtract 15 hrs from the 46 hrs she was gone; 46-15 = 31 hrs travel time
\n" ); document.write( "therefore:
\n" ); document.write( "(31-t) = amt of time to drive from Pitts back to K.C
\n" ); document.write( ";
\n" ); document.write( "The distance there and back is the same, write a dist equation; d = speed * time
\n" ); document.write( "55t = 50(31-t)
\n" ); document.write( "55t = 1550 - 50t
\n" ); document.write( "55t + 50t = 1550
\n" ); document.write( "105t = 1550
\n" ); document.write( "t = 14.76 hr to drive from K.C to Pitts
\n" ); document.write( ";
\n" ); document.write( "Find the distance
\n" ); document.write( "55 * 14.76 = 812 miles
\n" ); document.write( ":
\n" ); document.write( "Check the distance using the return trip, should be the same
\n" ); document.write( "50(31-14.76) = 812 mi also \n" ); document.write( "
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