document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880580>Question 880580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Square root of 6 * square root of 5 * square root of 4 * square root of 3 * square root of 2 * square root of 1 = k square root of 5 <BR>\n" );
document.write( "What is the value of k?<BR>\n" );
document.write( "Thnx  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531574 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Square root of 6 * square root of 5 * square root of 4 * square root of 3 * square root of 2 * square root of 1 = k square root of 5 <BR>\n" );
document.write( "we need the prime factors for each term<BR>\n" );
document.write( "(3^1/2 * 2^1/2) * 5^1/2 * (2^1/2 * 2^1/2) * 3^1/2 * 2^1/2 * 1^1/2<BR>\n" );
document.write( "combine like terms by adding their exponents and note 1^1/2 = 1<BR>\n" );
document.write( "3 * 2^2 * 5^1/2 = 12 * 5^1/2<BR>\n" );
document.write( "k = 12<BR>\n" );
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