document.write( "Question 880394: Two drain pipes can empty a pool in 17 1/2 minutes. The larger pipe can empty the pool in 12 minutes less than it would take the smaller pipe. How long will it take the smaller pipe to empty the pool alone? \n" ); document.write( "
Algebra.Com's Answer #531500 by ankor@dixie-net.com(22740)\"\" \"About 
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let x = time required by the smaller pipe to drain the pool alone
\n" ); document.write( "then
\n" ); document.write( "(x-12) = time required by the larger pipe
\n" ); document.write( "let completed job = 1; (a drained pool)
\n" ); document.write( ":
\n" ); document.write( "Two drain pipes can empty a pool in 17 1/2 minutes.
\n" ); document.write( " The larger pipe can empty the pool in 12 minutes less than it would take the smaller pipe.
\n" ); document.write( " How long will it take the smaller pipe to empty the pool alone?
\n" ); document.write( ":
\n" ); document.write( "\"17.5%2Fx\" + \"17.5%2F%28%28x-12%29%29\" = 1
\n" ); document.write( "multiply equation by x(x-12),
\n" ); document.write( "x(x-12)*\"17.5%2Fx\" + x(x-12)*\"17.5%2F%28%28x-12%29%29\" = x(x-12)
\n" ); document.write( "cancel the denominators and you have:
\n" ); document.write( "17.5(x-12) + 17.5x = x(x-12)
\n" ); document.write( "17.5x - 210 + 17.5x = x^2 - 12x
\n" ); document.write( "combine to form a quadratic equation on the right
\n" ); document.write( "0 = x^2 - 12x - 35x + 210
\n" ); document.write( "x^2 - 47x + 210 = 0
\n" ); document.write( "you can use the quadratic formula here, but this will factor to
\n" ); document.write( "(x-5)(x-42) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "x = 5; not possible
\n" ); document.write( "and
\n" ); document.write( "x = 42 min for small pipe to empty the pool alone
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that checks out. large pipe, 42 - 12 = 30 min
\n" ); document.write( "\"17.5%2F42+%2B+17.5%2F30\" =
\n" ); document.write( ".417 + .583 = 1
\n" ); document.write( "
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