document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880477>Question 880477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I am trying to figure out the value of x for a quadrilateral that the sum of the angle measures 360 degrees.  My equation given at the top was (5x + 5) and the second part of the equation given is 2x. How would I find x?  I believe you have to distribute the 2x to the (5x + 5), correct me if I am wrong.  Then you would have (10x + (5)2x)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531497 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In all convex quadrilaterals, like these,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C200%2C-3%2C33%2C-2%2C22%2Crectangle%280%2C0%2C30%2C20%29%29 ALIGN=MIDDLE  ALT=\"drawing%28300%2C200%2C-3%2C33%2C-2%2C22%2Crectangle%280%2C0%2C30%2C20%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C200%2C-3%2C33%2C-2%2C22%2C%0D%0Aline%280%2C0%2C27%2C0%29%2Cline%2830%2C18%2C27%2C0%29%2C%0D%0Aline%280%2C0%2C5%2C20%29%2Cline%2830%2C18%2C5%2C20%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "the measures of the interior angles add up to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%5Eo ALIGN=MIDDLE  ALT=\"360%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "If you know the measures of 3 of the angles, you can find the measure of the fourth angle.<BR>\n" );
document.write( " <BR>\n" );
document.write( "You may know that your quadrilateral is a parallelogram because you were told,<BR>\n" );
document.write( "or because it is drawn on grid/graph paper,<BR>\n" );
document.write( "or because the figure indicates that opposite sides are parallel with little arrows like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C200%2C-3%2C33%2C-2%2C22%2C%0D%0Aline%280%2C0%2C25%2C0%29%2Cline%2830%2C20%2C25%2C0%29%2C%0D%0Aline%280%2C0%2C5%2C20%29%2Cline%2830%2C20%2C5%2C20%29%2C%0D%0Aarrow%280%2C0%2C12%2C0%29%2Carrow%281%2C0%2C13%2C0%29%2C%0D%0Aarrow%285%2C20%2C17%2C20%29%2Carrow%286%2C20%2C18%2C20%29%2C%0D%0Aarrow%280%2C0%2C3%2C12%29%2Carrow%2825%2C0%2C28%2C12%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "In that case, opposite angles in the parallelogram have equal measures,<BR>\n" );
document.write( "and the measures of adjacent angles add up to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180%5Eo ALIGN=MIDDLE  ALT=\"180%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "So for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C200%2C-3%2C33%2C-2%2C22%2C%0D%0Aline%280%2C0%2C25%2C0%29%2Cline%2830%2C20%2C25%2C0%29%2C%0D%0Aline%280%2C0%2C5%2C20%29%2Cline%2830%2C20%2C5%2C20%29%2C%0D%0Aarrow%280%2C0%2C12%2C0%29%2Carrow%281%2C0%2C13%2C0%29%2C%0D%0Aarrow%285%2C20%2C17%2C20%29%2Carrow%286%2C20%2C18%2C20%29%2C%0D%0Aarrow%280%2C0%2C3%2C12%29%2Carrow%2825%2C0%2C28%2C12%29%2C%0D%0Alocate%285.5%2C20.5%2C%285x%2B5%29%5Eo%29%2Clocate%2825.5%2C20.5%2C%282x%29%5Eo%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > the equation you would use is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285x%2B5%29%2B2x=180 ALIGN=MIDDLE  ALT=\"%285x%2B5%29%2B2x=180\"   DISABLED_style= \"max-width:90%; height:auto;\" > ,<BR>\n" );
document.write( "but you would use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%2B5=2x ALIGN=MIDDLE  ALT=\"5x%2B5=2x\"   DISABLED_style= \"max-width:90%; height:auto;\" > for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C200%2C-3%2C33%2C-2%2C22%2C%0D%0Aline%280%2C0%2C25%2C0%29%2Cline%2830%2C20%2C25%2C0%29%2C%0D%0Aline%280%2C0%2C5%2C20%29%2Cline%2830%2C20%2C5%2C20%29%2C%0D%0Aarrow%280%2C0%2C12%2C0%29%2Carrow%281%2C0%2C13%2C0%29%2C%0D%0Aarrow%285%2C20%2C17%2C20%29%2Carrow%286%2C20%2C18%2C20%29%2C%0D%0Aarrow%280%2C0%2C3%2C12%29%2Carrow%2825%2C0%2C28%2C12%29%2C%0D%0Alocate%285%2C20.5%2C%285x%2B5%29%5Eo%29%2Clocate%2821%2C3%2C%282x%29%5Eo%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );