document.write( "Question 880432: The length of a rectangle is 10 feet longer than it is wide. If each side is increased 10 feet, then the area is multiplied by 2. What was the size of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #531484 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! w and L, width and length. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Each side is increased by 10 feet. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The increased dimensions makes area become \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find original w and L.\r \n" ); document.write( "\n" ); document.write( "Original area, \n" ); document.write( "Increased area, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We were given that increased area equals two times the original area: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "D=100-4*(-20)=100+80=180, sqrt(180)=sqrt(3*6*2*5)=sqrt(3*3*2*2*5)=6sqrt(5). \n" ); document.write( " \n" ); document.write( "Original width, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Original length, |