document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880260>Question 880260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At sea level, the weight of the atmosphere exerts a pressure of 14.7 pounds per square inch, commonly referred to as 1 atmosphere of pressure. As an object descends in water, pressure P and depth d are linearly related. In salt water, the pressure at a depth of 33 ft is 2 atms, or 29.4 pounds. per square inch. \r<BR>\n" );
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document.write( "1) Choose the correct linear model below. <BR>\n" );
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document.write( "a) P = 0.445d + 14.7 <BR>\n" );
document.write( "b) P = 2.245d - 33 <BR>\n" );
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document.write( "c) P = 0.445d + 29.4 <BR>\n" );
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document.write( "d) P = 0.03d + 1 \r<BR>\n" );
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document.write( "2) Choose the correct interpretation of the slope of the model below \r<BR>\n" );
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document.write( "a) It is the rate of change of pressure with respect to depth in units of lb/inē per foot <BR>\n" );
document.write( "b) It is the rate of change of depth with respect to pressure in units of feet per lb/inē \r<BR>\n" );
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document.write( "3) What is the pressure at a depth of 90 ft? \r<BR>\n" );
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document.write( "______ pounds per square inch (Round to the nearest integer as needed.) \r<BR>\n" );
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document.write( "4) What is the depth at which the pressure is 6 atms? \r<BR>\n" );
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document.write( "____ feet (simplify your answer.)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531468 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At sea level, the weight of the atmosphere exerts a pressure of 14.7 pounds per square inch, commonly referred to as 1 atmosphere of pressure. As an object descends in water, pressure P and depth d are linearly related. In salt water, the pressure at a depth of 33 ft is 2 atms, or 29.4 pounds. per square inch.<BR>\n" );
document.write( "1) Choose the correct linear model below.<BR>\n" );
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document.write( "a) P = 0.445d + 14.7<BR>\n" );
document.write( "Found by 14.7/33 = .445, plus the pressure of the air<BR>\n" );
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document.write( "2) Choose the correct interpretation of the slope of the model below<BR>\n" );
document.write( "a) It is the rate of change of pressure with respect to depth in units of lb/inē per foot<BR>\n" );
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document.write( "3) What is the pressure at a depth of 90 ft?<BR>\n" );
document.write( "______ pounds per square inch (Round to the nearest integer as needed.)<BR>\n" );
document.write( "P = .445(90) + 14.5<BR>\n" );
document.write( "P = 55 psi\r<BR>\n" );
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document.write( "4) What is the depth at which the pressure is 6 atms?<BR>\n" );
document.write( "____ feet (simplify your answer.)<BR>\n" );
document.write( "Find the pressure at 6 atms: 6 * 14.7 = 88.2<BR>\n" );
document.write( ".445d + 14.7 = 88.2<BR>\n" );
document.write( ".445d = 88.2 - 14.7<BR>\n" );
document.write( ".445d = 73.5<BR>\n" );
document.write( "d = 73.5/.445<BR>\n" );
document.write( "d = 165 ft is the depth at 6 atms\r<BR>\n" );
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document.write( "0 solutions<BR>\n" );
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