document.write( "Question 880364: Write a 3rd degree polynomial function that has zeros at x= -2, 4, 6 and also passes though the point (0,3
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Algebra.Com's Answer #531456 by KMST(5328) $\"\"$ $\"About$

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A 3rd degree polynomial with zeros at $\"x=-2\"$ , $\"x=4\"$ , and $\"x=6\"$ ,
\n" ); document.write( "must have the factoring $\"p%28x%29=a%28x-%28-2%29%29%28x-4%29%28x-6%29=a%28x%2B2%29%28x-4%29%28x-6%29\"$ .
\n" ); document.write( "If it \"passes though the point (0,3)\", then
\n" ); document.write( " $\"p%280%29=3\"$ , so
\n" ); document.write( " $\"a%280%2B2%29%28x-4%29%28x-6%29=3\"$ ---> $\"2%28-4%29-6%29a=3\"$ ---> $\"48a=3\"$ ---> $\"a=3%2F48\"$ --> $\"a=1%2F6\"$ .
\n" ); document.write( "So the polynomial is
\n" ); document.write( " $\"p%28x%29=%281%2F16%29%28x%2B2%29%28x-4%29%28x-6%29\"$ . \n" ); document.write( "

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