document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880398>Question 880398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> P,6 and r are three consecutive terms of a linear sequence.<BR>\n" );
document.write( "if r is twice the value of p,find the value of p and r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531412 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p,6,2p<BR>\n" );
document.write( "a[3] = p + (n-1)d<BR>\n" );
document.write( "a[3] = p + 2d = 2p, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+p%2F2 ALIGN=MIDDLE  ALT=\"d+=+p%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "p + p/2 = 6,  2p + p = 12, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+4 ALIGN=MIDDLE  ALT=\"p+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "{4,6,8)   d = 2 </SPAN>\n" );
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